Thursday, December 8, 2011
TopCoder - SRM 515 DIV 2 - FortunateNumbers - getFortunate
As you can see in the problem statement just a simple brute force is enough to pass the time limit. I produce all combinations of a[i] + b[j] + c[k] for all i, j, k and check whether it is a fortunate number or not, if yes I insert the number in a set and finally I return the size of the set.
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Link to the problem on Timus Online Judge First of all there are two kinds of input which the answer is zero, first if sum % 2 == 1 or se... -
Link to the problem on Timus Online Judge The problem statement is completely straight forward with no hidden tricks :). Yeah yeah I know...
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Link to the problem on Timus Online Judge This is a Computational Geometry problem. No 3 points lie on the same line and this is a great...
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