Rob Kolstad
Given a number base B (2 <= B <= 20 base 10), print all the integers N (1 <= N <= 300 base 10) such that the square of N is palindromic when expressed in base B; also print the value of that palindromic square. Use the letters 'A', 'B', and so on to represent the digits 10, 11, and so on.
Print both the number and its square in base B.
PROGRAM NAME: palsquare
INPUT FORMAT
A single line with B, the base (specified in base 10).SAMPLE INPUT (file palsquare.in)
10
OUTPUT FORMAT
Lines with two integers represented in base B. The first integer is the number whose square is palindromic; the second integer is the square itself.SAMPLE OUTPUT (file palsquare.out)
1 1 2 4 3 9 11 121 22 484 26 676 101 10201 111 12321 121 14641 202 40804 212 44944 264 69696
Brute force - base conversion - palindrome checking
Produce all the squares of numbers from 1 to 300, convert them to base b and check whether they are palindrome or not, if they are, convert the number to base b too and print both the number and it's square that has been converted to base b.
I have two functions in my solution, toBase( int, int ) and isPal( string ). In toBase() function I convert the given number to base b, and in function isPal() I check whether the given string is palindrome or not with two iterators to the beginning and to the end of the string.
There's no another solution more eficient?
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DeleteA better approach would be to generate palindrome for respective bases and check if they are squares. For example, for a base 2 we only need to do it for 32 such values.
ReplyDeleteThis will not work, try base 5, 6 (base 10), will be 11 in base (5), and the square (36) is 121 in base 10, and therefore you are wrong.
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