UVA - 10082 - WERTYU

problem statement

Ad Hoc

Easily you have to convert each character in the input to its left character on the keyboard.

string kb = "`1234567890-=QWERTYUIOP[]\\ASDFGHJKL;\'ZXCVBNM,./";

    while( getline(cin, line) )
    {
        for(int i = 0; i < line.size(); i ++)
            cout << (line[i] != ' ' ? kb[ kb.find(line[i]) - 1 ] : ' ');
        cout << endl;
    }

In this solution I saved all the keyboard in a string named kb, and for each character, I  find it in the string kb and print the previous character.
I use a good member function of class string, stringName.find( ch ) that return the position of ch in stringName or string::pos if ch is not in the string.